In a steady state of thermal conduction, the temperatures of the ends A and B of a 20 cm long rod are 10 0 ∘ C and 0 ∘ C respectively. What will be the temperature of the rod at a distance of 6 cm from the end A of the rod?

The gradient is 20 100 = 5 ∘ C c m − 1 . At 6 cm from A : 100 − 5 × 6 = 7 0 ∘ C. B.

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Physics - Heat & Thermo Question with Solution | TestHub

PhysicsHeat & ThermoHeat TransferMedium2 min

PhysicsMediumsingle choice

In a steady state of thermal conduction, the temperatures of the ends $A$ and $B$ of a 20 cm long rod are $10 0^{\circ}$ C and $0^{\circ}$ C respectively. What will be the temperature of the rod at a distance of 6 cm from the end $A$ of the rod?

Options:

Answer:

Solution:

The gradient is $\frac{100}{20} = 5^{\circ}$ C $c m^{- 1}$ . At 6 cm from $A$ : $100 - 5 \times 6 = 7 0^{\circ}$ C. B.

Subject:PhysicsTopic:Heat & ThermoSubtopic:Heat Transfer

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