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PhysicsHeat & ThermoKinetic Theory of Gases and Gas LawsMedium2 minQB

PhysicsMediumnumerical

Find the total mean rotational kinetic energy of 2 moles of a diatomic gas at 300 K, in joules (nearest 10 J). $R = 8.314 J / (mol K)$ .

Answer:

4990.00

Solution:

Per molecule kT, so for 2 moles $2 RT = 2 \times 8.314 \times 300 = 4988 J$ , which is 4990 J to the nearest 10 J .

Subject:PhysicsTopic:Heat & ThermoSubtopic:Kinetic Theory of Gases and Gas Laws

⏱ 2mℹ️ Source: QB

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