A drill of power P W drills a copper block of mass M kg and specific heat s J kg − 1 ∘ C − 1 . If 40\% of its power heats the machine, the block temperature rise in T seconds is:

Q = 0.6 PT . M s Δ T = Q . Δ T = ( M s ) 0.6 PT .

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Physics - Heat & Thermo Question with Solution | TestHub

PhysicsHeat & ThermoThermal ExpansionMedium2 minQB

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A drill of power $P$ W drills a copper block of mass $M kg$ and specific heat $s J kg^{- 1}^{\circ} C^{- 1}$ . If 40\% of its power heats the machine, the block temperature rise in $T$ seconds is:

Options:

Answer:

Solution:

$Q = 0.6 PT$ .

$M s Δ T = Q . Δ T = \frac{0.6 PT}{( M s )} .$

Subject:PhysicsTopic:Heat & ThermoSubtopic:Thermal Expansion

⏱ 2mℹ️ Source: QB

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