A glass container encloses gas at a pressure 4 × 1 0 5 Pa and 300 K temperature. The container walls can bear a maximum pressure of 8 × 1 0 5 Pa . If the temperature of the container is gradually increased, find the temperature at which the container will break :

Constant volume: T 1 P 1 = T 2 P 2 . T 2 = 300 × 4 × 1 0 5 8 × 1 0 5 = 600 K .

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Physics - Heat & Thermo Question with Solution | TestHub

PhysicsHeat & ThermoKTGMedium2 minQB

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A glass container encloses gas at a pressure $4 \times 1 0^{5} Pa$ and 300 K temperature. The container walls can bear a maximum pressure of $8 \times 1 0^{5} Pa$ . If the temperature of the container is gradually increased, find the temperature at which the container will break :

Options:

Answer:

Solution:

Constant volume: $\frac{P _{1}}{T _{1}} = \frac{P _{2}}{T _{2}}$ .

$T_{2} = 300 \times \frac{8 \times 1 0 ^{5}}{4 \times 1 0 ^{5}} = 600 K .$

Stream:JEESubject:PhysicsTopic:Heat & ThermoSubtopic:KTG

⏱ 2mℹ️ Source: QB

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