Equal masses of two liquids initially at 1 0 ∘ C and 7 0 ∘ C equilibrate at 3 0 ∘ C in an insulated vessel. Find the colder-liquid to hotter-liquid specific-heat ratio. Ignore vessel heat capacity.

m c c ( 30 − 10 ) = m c h ( 70 − 30 ) . c h c c = 20 40 = 2.

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PhysicsHeat & ThermoThermal ExpansionEasy2 minQB

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Equal masses of two liquids initially at $1 0^{\circ} C$ and $7 0^{\circ} C$ equilibrate at $3 0^{\circ} C$ in an insulated vessel. Find the colder-liquid to hotter-liquid specific-heat ratio. Ignore vessel heat capacity.

Answer:

Solution:

$m c_{c} (30 - 10) = m c_{h} (70 - 30)$ .

$\frac{c _{c}}{c _{h}} = \frac{40}{20} = 2.$

Subject:PhysicsTopic:Heat & ThermoSubtopic:Thermal Expansion

⏱ 2mℹ️ Source: QB

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