Start Free Mock LoginAlready registered? Login here

Physics - Heat & Thermo Question with Solution | TestHub

PhysicsHeat & ThermoThermodynamics Laws & Specific Heats of GasesMedium2 minQB

PhysicsMediumsingle choice

When a thermodynamic system is taken from state $A$ to state $B$ via path $A CB$ (Figure 3.84), 100 cal is given to the system and 60 cal worth of work is done. Along the path $A D B$ the work done is worth 20 cal. The heat flowing into the system in this case would be:

Options:

Answer:

Solution:

Along $A CB$ : $Δ U = 100 - 60 = 40$ cal. Along $A D B$ : $Q = Δ U + W = 40 + 20 = 60$ cal. D.

Subject:PhysicsTopic:Heat & ThermoSubtopic:Thermodynamics Laws & Specific Heats of Gases

⏱ 2mℹ️ Source: QB

Doubts & Discussion

Loading discussions...