A black ball of surface area 3 × 1 0 − 3 m² is at 500 K in a room at 300 K. Find the net rate of loss of heat, in W.

P = σ A ( T 4 − T 0 4 ) = 5.67 × 1 0 − 8 × 3 × 1 0 − 3 ( 50 0 4 − 30 0 4 ) = 9.3 W.

Physics - Heat & Thermo Question with Solution | TestHub

PhysicsHeat & ThermoHeat TransferMedium2 min

PhysicsMediumnumerical

A black ball of surface area $3 \times 1 0^{- 3}$ m² is at 500 K in a room at 300 K. Find the net rate of loss of heat, in W.

Answer:

9.30

Solution:

$P = σ A (T^{4} - T_{0}^{4}) = 5.67 \times 1 0^{- 8} \times 3 \times 1 0^{- 3} (50 0^{4} - 30 0^{4}) = 9.3$ W.

Subject:PhysicsTopic:Heat & ThermoSubtopic:Heat Transfer

⏱ 2m

Loading discussions...