A body of mass 100 g is moving in circular path of radius 2 m on vertical plane as shown in figure. The velocity of the body at point $A$ is $10 m / s$ . The ratio of its kinetic energies at point $B$ and $C$ is :

(Take acceleration due to gravity as $10 m / s^{2}$ )

Question

A body of mass 100 g is moving in circular path of radius 2 m on vertical plane as shown in figure. The velocity of the body at point $A$ is $10 m / s$ . The ratio of its kinetic energies at point $B$ and $C$ is :

(Take acceleration due to gravity as $10 m / s^{2}$ )

TestHub · Accepted Answer

​ 2 1 ​ m × 100 + 0 = 2 1 ​ mV B 2 ​ + mg ( R − 2 R 3 ​ ​ ) 100 = V B 2 ​ + 2 gR ( 1 − 2 3 ​ ​ ] V B 2 ​ = 100 − 20 ( 2 − 3 ​ ) V B 2 ​ = 60 + 20 3 ​ ) K . E B ​ = 2 1 ​ mV B 2 ​ = 2 m ​ ( 60 + 20 3 ​ ) 2 1 ​ m ( 100 ) = 2 1 ​ mV 2 100 = mg ( 2 3 R ​ ) 100 V C 2 ​ = 60 V C 2 ​ = 40 K . E C ​ = 2 1 ​ mV V C 2 ​ = 2 1 ​ m ( 40 ) K . E B ​ = 40 60 + 20 3 ​ ​ = 2 3 ​ + 2 3 ​ ​ = 2 3 + 3 ​ ​ ​

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