Start Free Mock LoginAlready registered? Login here

Physics - W.E.P. Question with Solution | TestHub

PhysicsW.E.P.Vertical circular motionEasy2 minQB

PhysicsEasysingle choice

A small block of mass $m$ slides along a smooth frictional track as shown in the figure. If it starts from rest at $P$ , what is the resultant force acting on it at $Q$ ?

Options:

Answer:

Solution:

From energy conservation,

$M g (4 R) = \frac{1}{2} {m v}^{2} \Rightarrow v = \sqrt{8 R g}$

At $θ, N = \frac{m v^{2}}{R} \Rightarrow N = \frac{m}{R} \times 8 g R = 8 m g$

So net force at $θ, F_{n e t} = \sqrt{N^{2} + {(m g)}^{2}} = \sqrt{65} m g$

Stream:JEESubject:PhysicsTopic:W.E.P.Subtopic:Vertical circular motion

⏱ 2mℹ️ Source: QB

Doubts & Discussion

Loading discussions...