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Physics - W.E.P. Question with Solution | TestHub

PhysicsW.E.P.Work kinetic energy theoremMedium

PhysicsMediumsingle choice

Passage / Comprehension

A 100 kg block is started with a speed of 4.0 m/s on a long, rough belt kept fixed in a horizontal position. The coefficient of kinetic friction between the block and the belt is 0.40.

The change in the internal energy of the block-belt system as the block comes to a stop on the belt is

Options:

Answer:

Solution:

$KE_{loss} = \frac{1}{2} \times 100 \times (4)^{2} = 800 J$

This loss converts into internal energy of the block-belt system: gain = 800 J.

Subject:PhysicsTopic:W.E.P.Subtopic:Work kinetic energy theorem

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