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PhysicsW.E.P.Calculation of workEasy2 minQB

PhysicsEasysingle choice

A wire fixed at the upper end stretches by length by applying a force F. The work done in stretching is

Answer:

Solution:

Work done $= \frac{1}{2} kx^{2} = \frac{1}{2} k ℓ^{2}$ where $ℓ$ is the total extensions. $= \frac{1}{2} (k ℓ) ℓ = \frac{1}{2} F ℓ$

Stream:JEESubject:PhysicsTopic:W.E.P.Subtopic:Calculation of work

⏱ 2mℹ️ Source: QB

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