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Physics - W.E.P. Question with Solution | TestHub

PhysicsW.E.P.Calculation of workMedium2 minQB

PhysicsMediuminteger

Force acting on a particle is $F = (α y \hat{i} + β xy \hat{j})$ . Find the work done by this force, when particle is moved along the line $2 x = 3 y$ from origin to the point $(3, 2)$ {take all quantities in SI units and $α = 1, β = 1$

Answer:

Solution:

$W = \int F \cdot d r$ $= \int (y d x + x y d y)$

On $2 x = 3 y$ : $x = \frac{3 y}{2}$ , $d x = \frac{3}{2} d y$ .

$W = \int_{0}^{2} (\frac{3 y}{2} + \frac{3 y ^{2}}{2}) d y$

$= [\frac{3 y ^{2}}{4} + \frac{y ^{3}}{2}]_{0}^{2}$ $= 3 + 4 = 7$ J.

Stream:JEESubject:PhysicsTopic:W.E.P.Subtopic:Calculation of work

⏱ 2mℹ️ Source: QB

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