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PhysicsW.E.P.Conservative force & potential energyEasy2 minQB

PhysicsEasysingle choice

Potential energy as a function of $r$ is given by $U = \frac{A}{r^{10}} - \frac{B}{r^{5}}$ , where $r$ is the interatomic distance, $A$ and $B$ are positive constants. The equilibrium distance between the two atoms will be :

Options:

Answer:

Solution:

Given $U = \frac{A}{r^{10}} - \frac{B}{r^{5}}$ .

Now, for equilibrium, $\frac{d U}{d r} = 0$ .

So, differentiating the given equation,

$\frac{- 10 A}{r^{11}} + \frac{5 B}{r^{6}} = 0$

$\Rightarrow \frac{10 A}{r^{11}} = \frac{5 B}{r^{6}} \Rightarrow r^{5} = \frac{2 A}{B} \Rightarrow r = {(\frac{2 A}{B})}^{\frac{1}{5}}$

Stream:JEESubject:PhysicsTopic:W.E.P.Subtopic:Conservative force & potential energy

⏱ 2mℹ️ Source: QB

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