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Physics - W.E.P. Question with Solution | TestHub

PhysicsW.E.P.Vertical circular motionEasy2 minQB

PhysicsEasynumerical

The mass of a pendulum bob is m = 2 kg and the length of the string is $l$ . It is displaced through $90 °$ from the vertical and released. What minimum tension (in N) should the string should be able to withstand so that it doesn't break during motion?

Answer:

60.00

Solution:

Velocity at the lowest point, $v = \sqrt{2 g l}$

At the lowest point, the tension in the string

$T = m g + \frac{m v^{2}}{l} = m g + \frac{m}{l} (2 g l) = 3 m g = 60 N$

Stream:JEESubject:PhysicsTopic:W.E.P.Subtopic:Vertical circular motion

⏱ 2mℹ️ Source: QB

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