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Physics - W.E.P. Question with Solution | TestHub

PhysicsW.E.P.Calculation of workMedium2 minQB

PhysicsMediumsingle choice

A spring of spring constant $5 \times 1 0^{3} N / m$ is stretched initially by $5 cm$ from the unstretched position. Then the work required to stretch it further by another $5 cm$ is

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Answer:

Solution:

Required work done $= \frac{1}{2} K (x_{2}^{2} - x_{1}^{2}) = \frac{1}{2} \times 5 \times 1 0^{3} [1 0^{2} - 5^{2}] \times 1 0^{- 4}$ $= \frac{1}{2} \times 5 \times 75 \times 1 0^{3} \times 1 0^{- 4} = 18.75$

Stream:JEESubject:PhysicsTopic:W.E.P.Subtopic:Calculation of work

⏱ 2mℹ️ Source: QB

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