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Physics - W.E.P. Question with Solution | TestHub

PhysicsW.E.P.MiscellaneousHard2 minQB

PhysicsHardnumerical

A closed circular tube of average radius $15 cm$ , whose inner walls are rough, is kept in vertical plane. A block of mass $1 kg$ just fit inside the tube. The speed of block is $22 m s^{- 1}$ , when it is introduced at the top of tube. After completing five oscillations, the block stops at the bottom region of tube. The work done by the tube on the block is ________ $J$ . (Given $g = 10 m s^{- 2}$ ).

Answer:

245.00

Solution:

The data given is
$r = 15 cm m = 1 kg v = 22 m s^{- 1}$
Total work done by the tube on the block is equal to loss in mechanical energy,
$w = \frac{1}{2} m v^{2} + m g h$
$\Rightarrow w = \frac{1}{2} \times 1 \times {(22)}^{2} + 1 \times 10 \times 0.3$
$\Rightarrow w = 245 J$

Stream:JEESubject:PhysicsTopic:W.E.P.Subtopic:Miscellaneous

⏱ 2mℹ️ Source: QB

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