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Physics - W.E.P. Question with Solution | TestHub

PhysicsW.E.P.Vertical circular motionEasy2 minQB

PhysicsEasysingle choice

The bob of a pendulum of mass $m$ and length $L$ is displaced $90 °$ from the vertical and gently released. In order that the string may not break upon passing through the lowest point, its minimum strength must be

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Answer:

Solution:

If $v$ is velocity of the bob on reaching the lowest point, then $\frac{1}{2} m v^{2} = m g L$

To avoid breaking, strength of the string

$T_{L} = \frac{m v^{2}}{L} + m g = \frac{2 m g L}{L} + m g = 3 m g$

Stream:JEESubject:PhysicsTopic:W.E.P.Subtopic:Vertical circular motion

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