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Physics - W.E.P. Question with Solution | TestHub

PhysicsW.E.P.Work kinetic energy theoremMedium2 minQB

PhysicsMediumsingle choice

A 5.0 kg object undergoes a time-varying force as shown in the graph below. If the velocity at $t = 0.0 s$ is +1.0 m/s, what is the velocity of the object at $t = 7 s$ ?

Question figure

Options:

Answer:

Solution:

From the force graph, the impulse is the area under F(t):

$J = \frac{1}{2} (3) (3) + \frac{1}{2} (3 + 1) (4) = 12.5 N s$

$Δ v = \frac{J}{m} = \frac{12.5}{5} = 2.5 m/s$

$v_{f} = v_{i} + Δ v = 1 + 2.5 = 3.5 m/s (C)$

Stream:JEESubject:PhysicsTopic:W.E.P.Subtopic:Work kinetic energy theorem

⏱ 2mℹ️ Source: QB

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