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PhysicsW.E.P.Vertical circular motionEasy2 minQB

PhysicsEasysingle choice

A stone of mass $m$ , tied to a string is being whirled in a vertical circle with a uniform speed. The tension in the string is

Options:

Answer:

Solution:

As the speed is constant, centripetal force required towards the centre of the circle will be same. At the top, direction of gravitational force and tension acting on the object will be same. Therefore, we can write,

$m g + T = \frac{m v^{2}}{r} \Rightarrow T = \frac{m v^{2}}{r} - m g$ .

Clearly in this case, tension in the string will be minimum.

Stream:JEESubject:PhysicsTopic:W.E.P.Subtopic:Vertical circular motion

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