Physics - W.E.P. Question with Solution | TestHub

PhysicsW.E.P.Calculation of workMedium2 minQB

PhysicsMediumsingle choice

The work done by a force $F = kx^{2}$ acting on a particle at an angle 60° with x-axis to displace it from $x = 2 m$ to $x = 3 m$ is :-

Answer:

Solution:

The component of force along the displacement is

$F_{x} = k x^{2} cos 6 0^{\circ} = \frac{k x ^{2}}{2}$

$W = \int_{2}^{3} F_{x} d x = \frac{k}{2} [\frac{x ^{3}}{3}]_{2}^{3}$

$W = \frac{k}{6} (27 - 8) = \frac{19 k}{6}$

Stream:JEESubject:PhysicsTopic:W.E.P.Subtopic:Calculation of work

⏱ 2mℹ️ Source: QB

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