Physics - W.E.P. Question with Solution | TestHub

Maximum acceleration of 1 kg block may be $a_{\max }=\mu g=1\mathrm{m}/{\mathrm{s}}^2$ Common acceleration without relative motion between two blocks may be, $a=\frac{0.5}{3}\mathrm{m}/{\mathrm{s}}^2$ Since, $a<a_{\max }$ There will be no relative motion and blocks will move with acceleration $\frac{0.5}{3}\mathrm{m}/{\mathrm{s}}^2$. Force of friction by lower block on upper block, $\begin{array}{rl}f& =ma=(1)\left(\frac{0.5}{3}\right)=\frac{1}{6}\mathrm{N}(\text{ towards right })\\ \therefore W& =f\times s\\ & =\frac{1}{6}\times 3=0.5\mathrm{J}\end{array}$