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Physics - W.E.P. Question with Solution | TestHub

PhysicsW.E.P.MiscellaneousEasy2 minPYQ_2020

PhysicsEasysingle choice

A long spring is stretched by $3 cm$ and its potential energy is $V$ . If the spring is stretched by $6 cm$ , its potential energy will be

Options:

Answer:

Solution:

$P . E . = \frac{1}{2} \times Y \times {(strain)}^{2} = \frac{1}{2} \times Y \times \frac{l^{2}}{L^{2}}$

or P.E $P . E . \propto l^{2}$

$∴ \frac{{(P . E)}_{2}}{{(P . E)}_{1}} = \frac{l_{2}^{2}}{l_{1}^{2}} = \frac{{(6)}^{2}}{{(3)}^{2}} = \frac{36}{9} = 4$

$∴ {(P . E .)}_{2} = 4 {(P . E)}_{1} = 4 V$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:W.E.P.Subtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2020

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