Physics - W.E.P. Question with Solution | TestHub

Power$=\frac{\text{Work}}{\mathrm{Time}}=\frac{\text{Force}\times \text{distance}}{\text{Time}}=\text{Force}\times \text{velocity}$

$\therefore \text{Force}\times \text{velocity}=\text{constant }\left(\mathrm{K}\right)$

or$(\mathrm{m}\mathrm{a})(\mathrm{at})=\mathrm{K}$

or$\mathrm{a}=(\frac{\mathrm{K}}{\mathrm{m}\mathrm{t}}{)}^{1/2}$

$\because \mathrm{s}=\frac{1}{2}\mathrm{at}{}^2$

$\therefore \mathrm{s}=\frac{1}{2}(\frac{\mathrm{K}}{\mathrm{m}\mathrm{t}}{)}^{1/2}\mathrm{t}{}^2=\frac{1}{2}(\frac{\mathrm{K}}{\mathrm{m}}{)}^{1/2}{\mathrm{t}}^{3/2}$

or$\mathrm{s}$is proportional to${\mathrm{t}}^{\raisebox{1ex}{$3$}\!\left/ \!\raisebox{-1ex}{$2$}\right.}$.