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PhysicsW.E.P.Conservative force & potential energyEasy2 minPYQ_2020

PhysicsEasysingle choice

A particle is released from a height $h$ , At a certain height; its kinetic energy is two times its potential energy. Height and speed of the particle at that instant are

Options:

Answer:

Solution:

Total mechanical energy= $m g h$

As, $\frac{K E}{P E} = \frac{2}{1}$

$K E = \frac{2}{3} m g h$

and $P E = \frac{1}{3} m g h$

Height from the ground at this instant,

$h^{,} = \frac{h}{3}$

and speed of the particle at this instant,

$v = \sqrt{2 g (h - h^{'})}$

$= \sqrt{2 g (\frac{2 h}{3})}$

$= 2 \sqrt{\frac{g h}{3}}$

Stream:JEESubject:PhysicsTopic:W.E.P.Subtopic:Conservative force & potential energy

⏱ 2mℹ️ Source: PYQ_2020

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