Physics - W.E.P. Question with Solution | TestHub

Let x be the maximum extension of the spring. From conservation of mechanical energy
Decrease in gravitational potential energy = increase in elastic potential energy

$\therefore \text{Mg x}=\frac{1}{2}{\text{kx}}^2$


or$\text{x}=\frac{2\text{Mg}}{\text{k}}$