Physics - W.E.P. Question with Solution | TestHub

Mass per unit length=$\frac{M}{L}$

$=\frac{4}{2}=2 \mathrm{k}\mathrm{g} {\mathrm{m}}^{-1}$




The mass of 0.6 m of chain

$=0.6\times 2=1.2 \mathrm{k}\mathrm{g}$

$\therefore$Center of mass of hanging part

$h=\frac{0.6+0}{2}=0.3 \mathrm{m}$

Hence, work done in pulling the chain on the table =work done against the gravity force

$W=mgh=1.2\times 10\times 0.3=3.6 \mathrm{J}$