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PhysicsW.E.P.Conservative force & potential energyEasy2 minPYQ_2020

PhysicsEasysingle choice

A particle is placed at the origin and a force $F = kx$ is acting on it (where $k$ is a positive constant). IF $U (0) = 0$ , the graph of $U (x)$ versus $x$ will be (where $U$ is the potential energy function)

Options:

Answer:

Solution:

$F = - \frac{dU}{dx} \Rightarrow \int dU = - \int Fdx$

$U_{2} - U_{1} = - [\int kxdx] \Rightarrow U = - \frac{1}{2} {kx}^{2}$

Stream:JEESubject:PhysicsTopic:W.E.P.Subtopic:Conservative force & potential energy

⏱ 2mℹ️ Source: PYQ_2020

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