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PhysicsW.E.P.MiscellaneousEasy2 minPYQ_2020

PhysicsEasysingle choice

A particle is released from a height $H$ . At certain height its kinetic energy is two times its potential energy. Height and speed of particle at that instant are

Options:

Answer:

Solution:

$∴ K + U = m g H$ & $K = 2 U$

$∴ 2 U + U = m g H$

$\Rightarrow U = \frac{m g H}{3} \Rightarrow m g h = \frac{m g H}{3} \Rightarrow h = H / 3$

$∴ \frac{1}{2} {m v}^{2} = 2 U = \frac{2 m g H}{3} \Rightarrow v = 2 \sqrt{\frac{g H}{3}}$

Subject:PhysicsTopic:W.E.P.Subtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2020

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