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Physics - W.E.P. Question with Solution | TestHub

PhysicsW.E.P.MiscellaneousEasy2 minPYQ_2020

PhysicsEasysingle choice

A body of mass $5 kg$ is thrown vertically up with a kinetic energy of $490 J$ . The height at which the kinetic energy of the body becomes half of the original value is : (take $g$ as $9.8 m s^{- 2}$ )

Options:

Answer:

Solution:

According to the law of conservation of energy

$\frac{1}{2} m u^{2} = \frac{1}{2} m v^{2} + m g h$

$490 = 245 + 5 \times 9.8 \times h$

$h = \frac{245}{49} = 5 m$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:W.E.P.Subtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2020

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