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PhysicsW.E.P.MiscellaneousEasy2 minPYQ_2020

PhysicsEasysingle choice

A long spring is stretched by $x cm$ its $P . E .$ is $U$ . If the same spring is stretched by $Nx cm$ the $P . E .$ stored in it will become

Answer:

Solution:

$U = \frac{1}{2} K x^{2}$

$U' = \frac{1}{2} K {(N x)}^{2} = \frac{1}{2} K x^{2} N^{2} = U N^{2}$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:W.E.P.Subtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2020

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