A particle is projected vertically upwards with a speed of 16 m s - 1 . After some time, when it again passes through the point of projection, its speed is found to be 8 m s - 1 . It is found that the

Question

A particle is projected vertically upwards with a speed of $16 m s^{- 1}$ . After some time, when it again passes through the point of projection, its speed is found to be $8 m s^{- 1}$ . It is found that the work done by air resistance is the same during the upward and downward motions. Then the maximum height attained by the particle is

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Answer:

A

Solution:

From work energy theorem for upward motion,

$\frac{1}{2} m {(16)}^{2} = m g h + W$

For downward motion,

$\frac{1}{2} m {(8)}^{2} = m g h - W$

$h = 8 m$

TestHub · Accepted Answer

From work energy theorem for upward motion, 1 2 m 16 2 = m g h + W For downward motion, 1 2 m 8 2 = m g h – W h = 8 m

Physics - W.E.P. Question with Solution | TestHub

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