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PhysicsW.E.P.MiscellaneousEasy2 minPYQ_2020

PhysicsEasysingle choice

A running man has half the kinetic energy of that of a boy of half of his mass. The man speeds up by 1 m/s so as to have same K.E. as that of the boy. The original speed of the man will be

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Answer:

Solution:

Let $m =$ mass of boy, $M =$ mass of man $v =$ velocity of boy, $V =$ velocity of man

$\frac{1}{2} M V^{2} = \frac{1}{2} [\frac{1}{2} m v^{2}]$ … (i)

$\frac{1}{2} M {(V + 1)}^{2} = 1 [\frac{1}{2} m v^{2}]$ …(ii)

Putting $m = \frac{M}{2}$ and solving $V = \frac{1}{\sqrt{2} - 1}$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:W.E.P.Subtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2020

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