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Physics - W.E.P. Question with Solution | TestHub

PhysicsW.E.P.MiscellaneousEasy2 minPYQ_2020

PhysicsEasysingle choice

A ball is released from the top of a tower. The ratio of work done by the force of gravity in 1^st second, 2^nd second and 3^rd second of the motion of the ball is

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Answer:

Solution:

Initial velocity of ball is zero ie., $u =$ $0$

$∴$ Displacement of ball in $t^{t h}$ second

$s = g t - \frac{1}{2} g =$ $g (t - \frac{1}{2})$

$s \propto (t - \frac{1}{2})$

or $s_{1} : s_{2} : s_{3} = (1 - \frac{1}{2}) : (2 - \frac{1}{2}) : (3 - \frac{1}{2})$

$= 1 : 3 :$ $5$

Now, $W =$ $m g s$

$W \propto s$

$∴ W_{1}$ $: W_{2} : W_{3} = 1 : 3 : 5$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:W.E.P.Subtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2020

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