Physics - W.E.P. Question with Solution | TestHub

Given, Power $(P)=$ constant Kinetic Energy (KE) $=\frac{1}{2}m{v}^2$ We know that, $P=\frac{KE}{\Delta t}\Rightarrow P=\frac{m{v}^2}{\Delta t}$ $\because P=$ constant. Hence, velocity of the body $v\propto \sqrt{t}$...(i) As, Velocity $v=\frac{ds}{dt}$...(ii) From Eqs. (i) and (ii), we get So, $\frac{ds}{dt}\propto \sqrt{t}$ Integrating the above cquation w.r.t. time $(t)$ $$\int \frac{ds}{dt}\propto \int \sqrt{t}$$ we get, displacement of the body $s\propto t^{3/2}$ Displacement $s=a{t}^{3/2}$, where $a$ is constant.