Physics - W.E.P. Question with Solution | TestHub

$\begin{array}{rl}& \text{ Given, velocity of particle }v=10\mathrm{m}/\mathrm{s}\\ & \text{ radius }\left(r^{\prime }\right)=5\mathrm{m}\\ & \text{ Angular displacement }(\theta )=60^{\circ }\\ & \therefore \theta =60\times \frac{\pi }{180}\mathrm{rad}\\ & \Rightarrow \theta =\frac{\pi }{3}\mathrm{rad}\\ & \end{array}$ When particle moves at an angle of $60^{\circ }$, then according to figure, displacement AB is equal to radius $r$ because it forms an equilateral triangle.$\therefore$ Average velocity $=\frac{\text{ displacement }\mathrm{AB}}{\text{ time }}=\frac{{\mathrm{r}}^{\prime }}{1}=5\mathrm{m}/\mathrm{s}$