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Physics - W.E.P. Question with Solution | TestHub

PhysicsW.E.P.Calculation of workEasy2 minPYQ_2019

PhysicsEasysingle choice

A force $F = 20 + 10 y$ acts on a particle in $y$ -direction where $F$ is in Newton and $y$ is in meter. Work done by this force to move the particle from $y = 0$ to $y = 1 m$ isNEET 2019 (All India)

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Answer:

Solution:

Work done is calculated by taking the dot product between the force and the displacement.
$W = \int F \cdot d y$
$= \int_{0}^{1} 20 d y + \int_{0}^{1} 10 y d y$
$= {[20 y]}_{0}^{1} + 5 {[y^{2}]}_{0}^{1}$
$= 20 + 5 = 25 J$

Stream:NEETSubject:PhysicsTopic:W.E.P.Subtopic:Calculation of work

⏱ 2mℹ️ Source: PYQ_2019

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