Start Free Mock LoginAlready registered? Login here

Physics - W.E.P. Question with Solution | TestHub

PhysicsW.E.P.Calculation of workMedium2 minPYQ_2016

PhysicsMediumsingle choice

Two wires are stretched through same distance. The force constant of second wire is half as that of the first wire. The ratio of work done to stretch first wire and second wire will be

Options:

Answer:

Solution:

AsW $= \frac{1}{2} k x^{2}$ If both wires are stretched through same distance, then $W \propto k$ . It is given that $k_{2} = \frac{k _{1}}{2}$ $∴ \frac{W _{1}}{W _{2}} = \frac{k _{1}}{k _{2}} = \frac{k _{1}}{\frac{k _{1}}{2}} = \frac{2}{1} = 2 : 1$

Stream:JIPMERSubject:PhysicsTopic:W.E.P.Subtopic:Calculation of work

⏱ 2mℹ️ Source: PYQ_2016

Doubts & Discussion

Loading discussions...