Physics - W.E.P. Question with Solution | TestHub

Efficiency of engine $\eta =60\%$. $\begin{array}{rl}\text{ Thus, power }& =\frac{\text{ work }/\text{ time }}{\eta }\\ & =\frac{100}{60}\times \frac{mgh}{t}\end{array}$ Given, $m=100\mathrm{kg},h=10\mathrm{m},t=5\mathrm{s}$ and $g=10{\mathrm{ms}}^{-2}$ $\begin{array}{rl}\text{ Hence, power }& =\frac{100}{60}\times \frac{100\times 10\times 10}{5}\\ & =3.3\times 10^3\mathrm{W}=3.3\mathrm{kW}\end{array}$