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Physics - W.E.P. Question with Solution | TestHub

PhysicsW.E.P.MiscellaneousEasy2 minPYQ_2014

PhysicsEasysingle choice

A body of mass $2 kg$ is thrown up vertically with kinetic energy of $490 J$ . The height at which the kinetic energy of the body becomes half of its original value is

Options:

Answer:

Solution:

Potential energy at the required height $= \frac{490}{2} = 245 J$ Again, $245 = 2 \times 10 \times h$ or $h = \frac{245}{20} m = 12.25 m$

Stream:AIIMSSubject:PhysicsTopic:W.E.P.Subtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2014

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