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Physics - W.E.P. Question with Solution | TestHub

PhysicsW.E.P.MiscellaneousEasy2 minPYQ_2012

PhysicsEasysingle choice

When a spring is stretched by $10 cm$ , the potential energy stored is $E$ . When the spring is stretched by $10 cm$ more, the potential energy stored in the spring becomes

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Answer:

Solution:

For 1st situation, $E = \frac{1}{2} k (10 \times 1 0^{- 2})^{2}$ For 2nd situation, $E^{'} = \frac{1}{2} k (20 \times 1 0^{- 2})^{2}$ On comparing Eqs. (i) and (ii), we get $E^{'} = 4 E$

Stream:WBJEESubject:PhysicsTopic:W.E.P.Subtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2012

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