Physics - W.E.P. Question with Solution | TestHub

Hints: $\mathrm{K}=\frac{{\mathrm{P}}^2}{2m}$ Here ${\mathrm{P}}^{\prime }=1.2\mathrm{P}$ Hence, $K^{\prime }=\frac{(1.2\mathrm{P}{)}^2}{2m}$ $${\mathrm{K}}^{\prime }=1.44\frac{{\mathrm{P}}^2}{2m}$$ ${\mathrm{K}}^{\prime }=1.44\mathrm{K}$ or Percentage increase in $\mathrm{K}=44\%$