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Physics - Wave Optics Question with Solution | TestHub

PhysicsWave OpticsYDSEEasy2 minQB

PhysicsEasysingle choice

In Young's double-slit experiment, the ratio of intensities of a bright band and a dark band is $16 : 1$ . The ratio of amplitudes of interfering waves will be

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Solution:

Since $\frac{I_{m a x .}}{I_{m i n .}} = \frac{16}{1}$

$\frac{{(\sqrt{I_{1}} + \sqrt{I_{2}})}^{2}}{{(\sqrt{I_{1}} - \sqrt{I_{2}})}^{2}} = \frac{16}{1}$

$\sqrt{I_{1}} + \sqrt{I_{2}} = 4 \sqrt{I_{1}} - 4 \sqrt{I_{2}}$

$A_{1} + A_{2} = 4 A_{1} - 4 A_{2}$

$3 A_{1} = 5 A_{2}$

$\Rightarrow \frac{A_{1}}{A_{2}} = \frac{5}{3}$

Stream:JEESubject:PhysicsTopic:Wave OpticsSubtopic:YDSE

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