Physics - Wave Optics Question with Solution | TestHub

For interference maxima, $d\sin \theta =n\lambda$ Here $d=2\lambda$ $\therefore \sin \theta =\mathrm{n}/2$ and is satisfied by 5 integral values of $\mathrm{n}(-2,-1,0,1,2)$, as the maximum value of $\sin \theta$ can only be 1 .