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Physics - Wave Optics Question with Solution | TestHub

PhysicsWave OpticsMiscellaneousEasy2 minQB

PhysicsEasynumerical

The earth is moving towards a fixed star with a velocity of $30 {km s}^{- 1}$ . An observer on the earth observes a shift of $0.58 Å$ in the wavelength of light coming from the star. What is the actual wavelength of light (in $μ m$ ) emitted by the star?

Answer:

0.58

Solution:

Using, $Δ λ = \frac{v}{c} λ$
Here $v = 30 {km s}^{- 1} = 3 \times 10^{4} {m s}^{- 1}$
$c = 3 \times 10^{8} {m s}^{- 1}$
$Δ λ = 0.58 \times 10^{- 10} m$
$∴ λ = \frac{c}{v} Δ λ$
$= \frac{3 \times 10^{8}}{3 \times 10^{4}} \times 0.58 \times 10^{- 10} m$
$= 0.58 \times 10^{- 6} m$
$= 0.58 μ m$

Stream:JEESubject:PhysicsTopic:Wave OpticsSubtopic:Miscellaneous

⏱ 2mℹ️ Source: QB

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