Physics - Wave Optics Question with Solution | TestHub

PhysicsWave OpticsDiffractionEasy2 minQB

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First diffraction minimum due to a single slit of width $10^{- 4} c m$ is at $θ = 30^{o} .$ The wavelength of the light used is

Answer:

Solution:

$a \sin θ = 1 \times λ$

$\Rightarrow λ = a \sin θ = 10^{- 4} \times \frac{1}{2} = \frac{10 \times 10^{- 5}}{2}$

$= 5 \times 10^{- 5} c m = 5000 Å$

Stream:JEESubject:PhysicsTopic:Wave OpticsSubtopic:Diffraction

⏱ 2mℹ️ Source: QB

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