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Physics - Wave Optics Question with Solution | TestHub

PhysicsWave OpticsMiscellaneousEasy2 minQB

PhysicsEasynumerical

In the adjacent diagram, $CP$ represents wavefront and $AO$ and $BP$ corresponding two rays. One particular condition on $θ$ for destructive interference at $P$ between the ray $BP$ and reflected ray $OP$ is $cosθ = \frac{λ}{nd}$ , where $n$ is

Answer:

2.00

Solution:

Path difference $= CO + OP + \frac{λ}{2}$

$= OPcos 2 θ + OP + \frac{λ}{2}$

$= OP (1 + \cos 2 θ) + \frac{λ}{2}$

$OPcosθ = d$

Path difference $= \frac{d}{cosθ} (1 + \cos 2 θ) + \frac{λ}{2}$

$= \frac{d}{cosθ} \cdot 2 \cos^{2} θ + \frac{λ}{2} = 2 dcosθ + \frac{λ}{2}$

$\Rightarrow 2 dcosθ = kλ (k \in N)$

For $k = 1$ , $2 dcosθ = λ$

$cosθ = \frac{λ}{2 d}$

Stream:JEESubject:PhysicsTopic:Wave OpticsSubtopic:Miscellaneous

⏱ 2mℹ️ Source: QB

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