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Physics - Wave Optics Question with Solution | TestHub

PhysicsWave OpticsYDSEEasy2 minQB

PhysicsEasysingle choice

In a double-slit experiment, the two slits are $1 mm$ apart and the screen is placed $1 m$ away. A monochromatic light of wavelength $500 nm$ is used. What will be the width of each slit for obtaining ten maxima of double-slit within the central maxima of a single-slit pattern?

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Answer:

Solution:

$d = 1 mm = 1 \times 10^{- 3} m$

$D = 1 m ., λ = 500 \times 10^{- 9} m$

Width of the central maximum $=$ width of 10 maxima in YDSE

$\frac{2 λ D}{a} = \frac{10 λ D}{d}$

$a = 0.2 d = 0 .2 mm$

Stream:JEESubject:PhysicsTopic:Wave OpticsSubtopic:YDSE

⏱ 2mℹ️ Source: QB

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