Two slits are separated by a distance of 0 .5 mm and illuminated with light of wavelength λ = 6000 A ∘ . If the screen is placed at 2 .5 m from the slits. The distance of the third bright fringe from the centre will be

The distance of n th bright fringe from the centre, x n = n D λ d So, x 3 = 3 × 2.5 × 6000 × 10 - 10 0.5 × 10 - 3 = 9 × 10 - 3 m = 9 mm

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PhysicsWave OpticsYDSEEasy2 minQB

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Two slits are separated by a distance of $0 .5 mm$ and illuminated with light of wavelength $λ = 6000 \overset{\circ}{A}$ . If the screen is placed at $2 .5 m$ from the slits. The distance of the third bright fringe from the centre will be

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Answer:

Solution:

The distance of $n^{th}$ bright fringe from the centre,

$x_{n} = \frac{n D λ}{d}$

So, $x_{3} = \frac{3 \times 2.5 \times 6000 \times 10^{- 10}}{0.5 \times 10^{- 3}}$

$= 9 \times 10^{- 3} m = 9 mm$

Stream:JEESubject:PhysicsTopic:Wave OpticsSubtopic:YDSE

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