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PhysicsWave OpticsYDSEMedium2 minPYQ_2026
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In the Young's double slit experiment, when a glass plate of thickness 't' is introduced in the path of one of the slits, the intensity at the position where the central maximum occurred previously remains unchanged. The minimum thickness of glass plate is [refractive index of glass plate = 1.5, wavelength of light in vacuum is ]

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Answer:
A
Solution:

Before introducing the glass plate, the central maximum has zero path difference and maximum intensity.

When a glass plate of thickness and refractive index is introduced in one of the paths, the path difference at the original central position becomes .

For the intensity at this position to remain unchanged, it must continue to be a maximum.

The condition for maximum intensity (constructive interference) is , where

For the minimum thickness of the glass plate, we take .



Substituting the given refractive index :





Stream:MHT_CETSubject:PhysicsTopic:Wave OpticsSubtopic:YDSE
⏱ 2mℹ️ Source: PYQ_2026

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