In Young's double slit experiment, the fringe width is 2.4 mm with light of wavelength 9000 A.U. If the light of wavelength 5400 A.U. is used, with no other change in the experimental set up. The

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In Young's double slit experiment, the fringe width is 2.4 mm with light of wavelength 9000 A.U. If the light of wavelength 5400 A.U. is used, with no other change in the experimental set up. The change in fringe width is

TestHub · Accepted Answer

The fringe width in Young's double slit experiment is given by $β = \frac{λ D}{d}$ .

Since $D$ and $d$ are constant, $β \propto λ$ .

$\frac{β _{2}}{β _{1}} = \frac{λ _{2}}{λ _{1}}$

Substituting the given values:

$β_{2} = 2.4 \times \frac{5400}{9000} = 2.4 \times \frac{3}{5} = 1.44$ mm

The change in fringe width is $Δ β = β_{1} - β_{2} = 2.4 - 1.44 = 0.96$ mm.

Answer: $0.96$ mm

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